The diaz family arrived for breakfast at a diner at 8:45 a.M .They stayed at the diner for 1 hour and 23 minutes. What time did the family leave the diner
Accepted Solution
A:
Answer:10:08 amStep-by-step explanation:Time at which Diaz family arrived at the diner = 8:45 a.mTime for which Diaz family stayed at the diner = 1 hour and 23 minutes To find the time at which Diaz family leave the diner Step 1add minutes 45 + 23 68as minutes cannot be greater than 60 so,subtract 60 from it 68 - 60 add one in the number of hours which they had stayed 1+1 = 2and reminder is the minutes now= 8Step 2 : add hours8 + 210step 3 join add and minutes10:08 am Diaz left the diner at 10:08 am