Please help!! I'll give 30 points to the brainliest!! Please help!!

Hey there :)

1st Shape:
A combination of a trapezium and a rectangle
We know the area formulas of rectangles → Area = length × width |
And Trapeziums → Area = [tex] \frac{1}{2} (base1+base2)(height)[/tex]

We are given:
Length of rectangle and base 2 of trapezium = 20 in
Width of rectangle = 16 in
Base 1 of trapezium = 9 in
Height of trapezium = 21 - 16 = 5 in

Apply the formulas
Area of rectangle = 20 × 16 = 320 in²
Area of trapezium = [tex] \frac{1}{2} [/tex] ( 9 + 20 )(5) = 72.5 in²

Add both areas if necessary = 320 + 72.5 = 392.5 in²

2nd Shape:
It is a trapezium

We know the area formula of a trapezium
Area = [tex] \frac{1}{2}(base 1 + base 2 )(height) [/tex]

We know the
Base 1 = 8 units
Base 2 = 16 units
Height = 14 units

Apply the formula
Area = [tex] \frac{1}{2} (8+16)(14)[/tex] = 168 units²
         
3rd Shape:
It is a trapezium

We know the:
Base 1 = 7 units
Base 2 = 24 units
Height = 24 units

Apply the formula
Area = [tex] \frac{1}{2}(7+24)(24) [/tex] = 372 units²

4th Shape:
It is a trapezium

We know the:
Base 1 = 4 units
Base 2 = 8 units
Height = 6 units

Apply the formula:
Area = [tex] \frac{1}{2} ( 4 + 8 )(6)[/tex] = 36 units²