Find the standard form equation that has a slopeof 1/2 and passes through the point (2,-7)

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:[tex]y = mx + b[/tex]Where:m: It's the slopeb: It is the cut-off point with the y axisAccording to the statement we have to:[tex]m = \frac {1} {2}[/tex]So, the equation is of the form:[tex]y = \frac {1} {2} x + b[/tex]We substitute the given point and find "b":[tex]-7 = \frac {1} {2} (2) + b\\-7 = 1 + b\\-7-1 = b\\b = -8[/tex]Finally, the equation is:[tex]y = \frac {1} {2} x-8[/tex]By definition, the standard form of the equation of the line is:[tex]ax + by = c[/tex]Then, we manipulate the equation algebraically:[tex]y = \frac {1} {2} x-8\\y + 8 = \frac {1} {2} x\\2 (y + 8) = x\\2y + 16 = x\\x-2y = 16[/tex]Answer:The equation in the standard form is:[tex]x-2y = 16[/tex]