Q:

4.9t^2-2.78t-1.15=0 what is the value of T

Accepted Solution

A:
Answer:t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490Step-by-step explanation:Solve for t: 4.9 t^2 - 2.78 t - 1.15 = 0 4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20: (49 t^2)/10 - (139 t)/50 - 23/20 = 0 Multiply both sides by 10/49: t^2 - (139 t)/245 - 23/98 = 0 Add 23/98 to both sides: t^2 - (139 t)/245 = 23/98 Add 19321/240100 to both sides: t^2 - (139 t)/245 + 19321/240100 = 75671/240100 Write the left hand side as a square: (t - 139/490)^2 = 75671/240100 Take the square root of both sides: t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490 Add 139/490 to both sides: t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490 Add 139/490 to both sides: Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490